# Line slope calculator 9x+y=28

**Straight line given by points A[2; 10] and B[3; 1]**

## Calculation:

**Slope-intercept form of line:**y = -9x+28

**Canonical form of the line equation:**9x+y-28 = 0

**Parametric form of the line equation:**

x = t+2

y = -9t+10 ; t ∈ R

**Slope:**m = -9

**Slope angle of line: φ =**-83°39'35″ = -1.4601 rad

**X intercept:**x

_{0}= 3.1111

**Y intercept:**y

_{0}= q = 28

**Distance line from the origin:**d

_{0}= 3.0921

**The length of the segment AB: |AB| =**9.0554

**Vector: AB =**(1; -9)

**Normal vector: n =**(9; 1)

**Midpoint of the segment AB: M =**[2.5; 5.5]

**Perpendicular Bisector equation:**x-9y+47 = 0

**Vector OA = (2; 10) ; |OA| = 10.198**

**Vector OB = (3; 1) ; |OB| = 3.1623**

**Scalar product OA .OB = 16**

**Angle ∠ AOB = 60°15'18″ = 1.0517 rad**