# Line slope calculator 10x-3y=40

**Straight line given by points A[4; 0] and B[7; 10]**

## Calculation:

**Slope-intercept form of line:**y = 3.3333x-13.3333

**Canonical form of the line equation:**10x-3y-40 = 0

**Parametric form of the line equation:**

x = 3t+4

y = 10t ; t ∈ R

**Slope:**m = 3.3333

**Slope angle of line: φ =**73°18'3″ = 1.2793 rad

**X intercept:**x

_{0}= 4

**Y intercept:**y

_{0}= q = -13.3333

**Distance line from the origin:**d

_{0}= 3.8313

**The length of the segment AB: |AB| =**10.4403

**Vector: AB =**(3; 10)

**Normal vector: n =**(10; -3)

**Midpoint of the segment AB: M =**[5.5; 5]

**Perpendicular Bisector equation:**3x+10y-66.5 = 0

**Vector OA = (4; 0) ; |OA| = 4**

**Vector OB = (7; 10) ; |OB| = 12.2066**

**Scalar product OA .OB = 28**

**Angle ∠ AOB = 55°29″ = 0.9601 rad**