In How Many Ways Can The Letters Of The Word Mathematics Be Arranged?

How many different ways can the letters of the word mathematics be arranged so that the vowels always come together?

In 4989600 distinct ways, the letter of the word ‘ Mathematics ‘ can be written. (i) When vowels are taken together: In the word ‘ Mathematics ‘, we treat the vowels A, E, A, I as one letter. Thus, we have MTHMTCS (AEAI).

How many words can be formed out of letters of the word mathematics in how many of these words are consonants together?

(i) There are 11 letters in the word ‘ MATHEMATICS ‘. Out of these letters M occurs twice, A occurs twice, T occurs twice and the rest are all different. =11! (2!)

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How many ways can parallel be arranged?

PARALLEL has 8 letters with one letter appearing 3 times and 1 letter appearing 2 times. The letters can be arranged in 8!/(3!* 2!) = 3360 ways.

How many ways can the word leader be arranged?

In how many ways can the letters of the word ‘LEADER’ be arranged? E. 6! = 360.

How many three letter words are formed using the letters of the word time?

How many three letter words are formed using the letters of the word TIME? Explanation: The number of letters in the given word is four. The number of three letter words that can be formed using these four letters is ⁴P₃ = 4 * 3 * 2 = 24.

How many consonants are in the word mathematics?

The fraction of the consonants in the word ‘ mathematics ‘ is 7/11. There are a total of 11 letters in the word, of which 4 (a, e, a, i) are vowels and 7 (m, t, h, m, t, c, s) are consonants.

How many 3 letter words with or without meaning can be formed?

= 720. Hence, the no. of 3 letter words formed from the word LOGARITHMS without repetition is 720. Hence the correct option of this question is option (a).

How many distinct ways can letters be arranged?

= 2494800 ways of arranging it.

How many ways 5 towels can be put into 4 boxes?

Since there are 5 letters and each letter can be posted in 4 ways. So, total number of ways in which all the five letters can be posted = 4 × 4 × 4 × 4 × 4 = 45.

How many ways can we arrange all the letters such that the last two letters are vowels?

If the last letter also has to be a vowel, then it can be any one of the remaining 3 vowels. After we have selected the two vowels for the first and last positions, we have 6 letters left, of which 2 repeat. Thus, the number of ways to arrange these in-between letters is 6!/ 2! = 720/ 2 = 360.

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How many permutations are in the word banana?

B – 1 A – 3 N – 2 So total no of words possible is factorial(6) ie 6! but we must remove duplicate words: ie- (6!/(2!* 3!)) which gives 60 So 60 distinguishable permutation of the letters in BANANA.

How many words can be formed by 2 vowels and 3 consonants out of 4 vowels and 7 consonants?

Out of 7 consonants and 4 vowels, how many words of 3 consonants and 2 vowels can be formed? = 210.

How many 4 letter words with or without meaning can be formed logarithms?

There are 10 letters in the word LOGARITHMS. So, the number of 4-letter words is equal to the number of arrangements of 10 letters, taken 4 at a time, i.e.,. 10P4= 5040.

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