# Line slope calculator 6x+y=50

**Straight line given by points A[7; 8] and B[8; 2]**

## Calculation:

**Slope-intercept form of line:**y = -6x+50

**Canonical form of the line equation:**6x+y-50 = 0

**Parametric form of the line equation:**

x = t+7

y = -6t+8 ; t ∈ R

**Slope:**m = -6

**Slope angle of line: φ =**-80°32'16″ = -1.4056 rad

**X intercept:**x

_{0}= 8.3333

**Y intercept:**y

_{0}= q = 50

**Distance line from the origin:**d

_{0}= 8.2199

**The length of the segment AB: |AB| =**6.0828

**Vector: AB =**(1; -6)

**Normal vector: n =**(6; 1)

**Midpoint of the segment AB: M =**[7.5; 5]

**Perpendicular Bisector equation:**x-6y+22.5 = 0

**Vector OA = (7; 8) ; |OA| = 10.6301**

**Vector OB = (8; 2) ; |OB| = 8.2462**

**Scalar product OA .OB = 72**

**Angle ∠ AOB = 34°46'40″ = 0.607 rad**