# Line slope calculator 4x+y=6

**Straight line given by points A[0; 6] and B[1; 2]**

## Calculation:

**Slope-intercept form of line:**y = -4x+6

**Canonical form of the line equation:**4x+y-6 = 0

**Parametric form of the line equation:**

x = t

y = -4t+6 ; t ∈ R

**Slope:**m = -4

**Slope angle of line: φ =**-75°57'50″ = -1.3258 rad

**X intercept:**x

_{0}= 1.5

**Y intercept:**y

_{0}= q = 6

**Distance line from the origin:**d

_{0}= 1.4552

**The length of the segment AB: |AB| =**4.1231

**Vector: AB =**(1; -4)

**Normal vector: n =**(4; 1)

**Midpoint of the segment AB: M =**[0.5; 4]

**Perpendicular Bisector equation:**x-4y+15.5 = 0

**Vector OA = (0; 6) ; |OA| = 6**

**Vector OB = (1; 2) ; |OB| = 2.2361**

**Scalar product OA .OB = 12**

**Angle ∠ AOB = 26°33'54″ = 0.4636 rad**