# Line slope calculator 7x+3y=52

**Straight line given by points A[4; 8] and B[7; 1]**

## Calculation:

**Slope-intercept form of line:**y = -2.3333x+17.3333

**Canonical form of the line equation:**7x+3y-52 = 0

**Parametric form of the line equation:**

x = 3t+4

y = -7t+8 ; t ∈ R

**Slope:**m = -2.3333

**Slope angle of line: φ =**-66°48'5″ = -1.1659 rad

**X intercept:**x

_{0}= 7.4286

**Y intercept:**y

_{0}= q = 17.3333

**Distance line from the origin:**d

_{0}= 6.8279

**The length of the segment AB: |AB| =**7.6158

**Vector: AB =**(3; -7)

**Normal vector: n =**(7; 3)

**Midpoint of the segment AB: M =**[5.5; 4.5]

**Perpendicular Bisector equation:**3x-7y+15 = 0

**Vector OA = (4; 8) ; |OA| = 8.9443**

**Vector OB = (7; 1) ; |OB| = 7.0711**

**Scalar product OA .OB = 36**

**Angle ∠ AOB = 55°18'17″ = 0.9653 rad**